Precisely! Scalar multiplication is very simple. We just have to multiply the x- and the y-components ($$3$$ and $$-2$$ respectively) by $$5$$, that's it!
If $$\vec{A} = \hat{i} - \hat{j}$$, $$\vec{B} = - 2 \hat{i} + 3 \hat{j}$$ and $$\vec{C} = 2 \hat{i} + \hat{j}$$, what is $$3 \vec{A} - 2 \vec{B} + 4 \vec{C}$$?
• $$15 \hat{i} - 5 \hat{j}$$
• $$9 \hat{i} + 7 \hat{j}$$
• $$-9 \hat{i} - 7 \hat{j}$$
• $$12 \hat{i} - 5 \hat{j}$$