Precisely! Scalar multiplication is very simple. We just have to multiply the x- and the y-components (\(3\) and \(-2\) respectively) by \(5\), that's it!

If \(\vec{A} = \hat{i} - \hat{j}\), \(\vec{B} = - 2 \hat{i} + 3 \hat{j}\) and \(\vec{C} = 2 \hat{i} + \hat{j}\), what is \(3 \vec{A} - 2 \vec{B} + 4 \vec{C}\)?

- \(15 \hat{i} - 5 \hat{j}\)
- \(9 \hat{i} + 7 \hat{j}\)
- \(-9 \hat{i} - 7 \hat{j}\)
- \(12 \hat{i} - 5 \hat{j}\)