Super! $$\vec{A} = 3\hat{i} - 4\hat{j}$$, $$\vec{B} = 10\hat{i} + 2\hat{j}$$ and $$\vec{C} = 8\hat{i} - 10\hat{j}$$, what is $$\vec{A} + \vec{B} + \vec{C}$$. You just add all the x-components of the vectors (that is, $$3, \, 10, \, 8$$) to get $$21$$ for the x-component of the final vector. Similarly, you add the y-components ($$4, \, 2, \, 10$$) to get the y-component of the final vector.
Look at the image here to understand how to perform $$\vec{A} - \vec{B}$$
If $$\vec{A} = 8\hat{i} + 4\hat{j}$$, $$\vec{B} = 10\hat{i} + 2\hat{j}$$, what is $$\vec{A} - \vec{B}$$?
• $$2\hat{i} + 2\hat{j}$$
• $$-2\hat{i} - 2\hat{j}$$
• $$2\hat{i} - 2\hat{j}$$
• $$-2\hat{i} + 2\hat{j}$$