Super! \(\vec{A} = 3\hat{i} - 4\hat{j}\), \(\vec{B} = 10\hat{i} + 2\hat{j}\) and \(\vec{C} = 8\hat{i} - 10\hat{j}\), what is \(\vec{A} + \vec{B} + \vec{C}\). You just add all the x-components of the vectors (that is, \(3, \, 10, \, 8\)) to get \(21\) for the x-component of the final vector. Similarly, you add the y-components (\(4, \, 2, \, 10\)) to get the y-component of the final vector.

Subtracting two vectors is very similar to adding two vectors. Instead of adding the second vector's component to the first vector's components, you subtract it.

Look at the image here to understand how to perform \(\vec{A} - \vec{B}\)

Look at the image here to understand how to perform \(\vec{A} - \vec{B}\)

If \(\vec{A} = 8\hat{i} + 4\hat{j}\), \(\vec{B} = 10\hat{i} + 2\hat{j}\), what is \(\vec{A} - \vec{B}\)?

- \(2\hat{i} + 2\hat{j}\)
- \(-2\hat{i} - 2\hat{j}\)
- \(2\hat{i} - 2\hat{j}\)
- \(-2\hat{i} + 2\hat{j}\)