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Awesome, as Jerry was initially travelling at 2.5 m/s, \(u = 2.5 \, \mathrm{m/s}\). As he finally reached a velocity of 5 m/s, \(v = 5 \, \mathrm{m/s}\). And, as he took a time interval of 2 s for all this, \(t = 2 \, \mathrm{m/s}\). We also calculated the acceleration \(a\) to be \(1.25 \, \mathrm{m/s^2}\).
Using all these variables, we get \(s = 2.5*2 + \frac{1}{2}*1.25*2^2\). That is, \(s = 5 + \frac{1}{2}*1.25*4\). So, \(s = 7.5 \, \mathrm{m}\).