Recall that velocity is the change in displacement, divided by the time taken for that change: \(v = \frac{dr}{dt}\). So, graphically, velocity is nothing but the

**slope**of the position-time graph.Look at the slopes at the 4 different points on the graph for the falling object. Just by looking at the figure, choose the time at which the tangent has the

**highest slope**(ignore the negative sign for now).- \(t = 1 \, \mathrm{s}\)
- \(t = 2 \, \mathrm{s}\)
- \(t = 3 \, \mathrm{s}\)
- \(t = 4 \, \mathrm{s}\)