It is now time to introduce the final EOM. The

\(v^2 = u^2 + 2*a*s\)

The final velocity \(v\), the initial velocity \(u\), the acceleration \(a\) and the displacement \(s\) satisfy this equation.

**3rd EOM**says,\(v^2 = u^2 + 2*a*s\)

The final velocity \(v\), the initial velocity \(u\), the acceleration \(a\) and the displacement \(s\) satisfy this equation.

Imagine that you throw a ball up in the air. The ball

**leaves your hand**with a speed of \(10 \, \mathrm{m/s}\). It goes up to a**maximum height**of \(5 \, \mathrm{m}\). Which of the following would you use to determine the acceleration it experienced when it travelled**upwards**?*(Hint: Whenever the maximum height of an object is mentioned, think of this: what is the object's final velocity when the object is at the maximum height?)*3rd EOM with \(v = 10 \, \mathrm{m/s}\) and \(s = 5 \, \mathrm{m}\)

3rd EOM with \(u = 10 \, \mathrm{m/s}\) and \(s = -5 \, \mathrm{m}\)

3rd EOM with \(u = 10 \, \mathrm{m/s}\) and \( s = 5 \, \mathrm{m}\)

3rd EOM with \(v = 10 \, \mathrm{m/s}\) and \(s = -5 \, \mathrm{m}\)