Let us look at the 2nd EOM:

\(s = u*t + \frac{1}{2}*a*t^2\)

Here, \(s\) is the

Remember that \(\text{Speed} = \frac{\text{Distance Covered}}{\text{Time Taken}}\) works

\(s = u*t + \frac{1}{2}*a*t^2\)

Here, \(s\) is the

**displacement**of the object.Remember that \(\text{Speed} = \frac{\text{Distance Covered}}{\text{Time Taken}}\) works

**only for average speed**. If the object is accelerating, then, we**cannot**use the value of the initial speed and the time taken to calculate the distance covered!We just calculated Jerry's acceleration to be 1.25 m/s

^{2}. Using the 2nd EOM, what is the value for Jerry's**displacement**, \(s\)? (Recall that Jerry's velocity changed from 2.5 m/s at 2 s to 5 m/s at 4 s.)\(s = 5*2 + \frac{1}{2}*1.25*2^2\)

\(s = 2.5*2 + \frac{1}{2}*1.25*2^2\)

\(s = 2.5*2 + \frac{1}{2}*5*2^2\)

\(s = 2.5*5 + \frac{1}{2}*1.25*2.5^2\)