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Smart! We have \(5\) electrons. The \(n=1\) orbit can have a maximum of \(2\) electrons. So, we put the \(2\) electrons there. We can't put more electrons into this orbit. So, the \(3\) electrons have to go to the \(n=2\) orbit, as this orbit can have a maximum of \(8\) electrons.
Which of the following electron distributions is invalid?
  • \(2\) in \(n=1\), \(8\) in \(n=2\) and \(4\) in \(n=3\)
  • \(2\) in \(n=1\), \(6\) in \(n=2\) and \(4\) in \(n=3\)
  • \(2\) in \(n=1\) and \(8\) in \(n=2\)
  • \(2\) in \(n=1\) and \(4\) in \(n=2\)