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Excellent! \(N\) is the only force that acts upwards. So, it has a positive sign in front of it. \(F\) and the weight \(m g\) are acting downwards, so, they have negative signs in front of them.
What is the equation for the normal force N in this situation?
  • \(N - F \cos \theta - mg = 0\)
  • \(N + F \sin \theta - mg = 0\)
  • \(N \sin \theta - F - mg = 0\)
  • \(N \cos \theta - F - mg = 0\)