Awesome! \(F = m a\). We know that \(m = 5\). As the object is going down, \(a = -9.8 \). Therefore, \(F = 5 \times -9.8\).

What if the same ball sits on a table without moving down? What is the net force on it?

- \(0\)
- \(5 \times 9.8\)
- \(5 \times -9.8\)
- \(\frac{5}{-9.8}\)