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Awesome! \(F = m a\). We know that \(m = 5\). As the object is going down, \(a = -9.8 \). Therefore, \(F = 5 \times -9.8\).
What if the same ball sits on a table without moving down? What is the net force on it?
  • \(0\)
  • \(5 \times 9.8\)
  • \(5 \times -9.8\)
  • \(\frac{5}{-9.8}\)