Smart! From \(F_x = m a_x\), we have \(a_x = \frac{F_x}{m}\). \(F_x\), the x-component of the force is the \(\cos\) component as we have discussed before. Similarly for \(F_y\).

We know that if a ball is falling freely, it accelerates downwards at \(g = 9.8 \, \mathrm{m/s^2}\). If an object has a mass of \(5 \, \mathrm{kg}\), what is the force that the Earth exerts on the object in Newtons? (Remember that Force is a vector.)

- \(0\)
- \(5 \times 9.8\)
- \(5 \times -9.8\)
- \(\frac{5}{-9.8}\)