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Smart! From \(F_x = m a_x\), we have \(a_x = \frac{F_x}{m}\). \(F_x\), the x-component of the force is the \(\cos\) component as we have discussed before. Similarly for \(F_y\).
We know that if a ball is falling freely, it accelerates downwards at \(g = 9.8 \, \mathrm{m/s^2}\). If an object has a mass of \(5 \, \mathrm{kg}\), what is the force that the Earth exerts on the object in Newtons? (Remember that Force is a vector.)
  • \(0\)
  • \(5 \times 9.8\)
  • \(5 \times -9.8\)
  • \(\frac{5}{-9.8}\)