Wonderful! The net displacement of the ball is \(0\) because it returns to its initial position. As velocity is displacement divided by time taken, the velocity will be \(0\).
The numerical value of position increases as you go to the right, or as you go up; it decreases as you go to the left, or you go down.

Because we are considering motion in one-dimension (1-D), you can either go up/down, or right/left. 2-D motion is a combination of going horizontally as well as vertically. We don't cover 2-D motion in this Chapter. We will do it in the next Chapter!